Mr. Ram has a beaker containing M millimeters of solution to distribute to the students in his class. If he gives each student 4 millimeters of solution, he will have 5 millimeters left over. In order to give each student 5 millimeters of solution, He will need an additional 21 millimeters. How many students are there in the class?
Choice D is correct.
Let S be the number of students in the class.
According to the question, we have
M – 4S = 5 and 5S = M + 21.
By substituting M = 5 +4S in the second equation, we have
5S = 5 + 4S + 21
Or S = 26.