For what value of x is |x−2| + 1 equal to 0?
D) There is no such value of x.
Choice D is correct.
If |x−2| + 1 = 0
Then |x−2| = -1
Since, the LHS is an absolute value of x−2, which can never be negative
Hence, |x−2| = -1 has no solution.
Therefore, there exists no value x for which |x−2| + 1 = 0.