Since, the ratio of the area of the larger pen to the smaller pen is 6:1
Also, the area of the larger pen is 48 square yards
Therefore, the area of larger pen can be calculated by
6/1 = 48/area of smaller pen
Therefore, area of smaller pen = 8 square yards.
Now from the questions we have, each pen can hold 1 pig for 2 square yards of its area.
Therefore, the number of pigs that the large pen and smaller pen can hold are 48/2, 8/2 respectively.
The difference (24 -4 = 20) gives us the number of pigs the larger pen can hold more than the smaller pen.